CSharp  Java  Python  Swift  GO  WPF  Ruby  Scala  F#  JavaScript  SQL  PHP  Angular  HTML
Program to determine whether a given number is a Disarium numberExplanationIn this program, we need to check whether the given number is Disarium or not. Disarium number A number is said to be the Disarium number when the sum of its digit raised to the power of their respective positions is equal to the number itself. For example, 175 is a Disarium number as follows 1^{1} + 7^{2} + 5^{3} = 1 + 49 + 125 = 175 Some of the other examples of Disarium number are 89, 135, 518 etc. To find whether given number is Disarium or not, calculate the sum of digits powered with their respective positions. If the sum is equal to the original number then, the given number is Disarium number. Algorithm
SolutionPython#calculateLength() will count the digits present in a number def calculateLength(n): length = 0; while(n != 0): length = length + 1; n = n//10; return length; num = 175; rem = sum = 0; len = calculateLength(num); #Makes a copy of the original number num n = num; #Calculates the sum of digits powered with their respective position while(num > 0): rem = num%10; sum = sum + int(rem**len); num = num//10; len = len  1; #Checks whether the sum is equal to the number itself if(sum == n): print(str(n) + " is a disarium number"); else: print(str(n) + " is not a disarium number"); Output: 175 is a disarium number C#include <stdio.h> //calculateLength() will count the digits present in a number int calculateLength(int n){ int length = 0; while(n != 0){ length = length + 1; n = n/10; } return length; } int main() { int num = 175, sum = 0, rem = 0, n; int len = calculateLength(num); //Makes a copy of the original number num n = num; //Calculates the sum of digits powered with their respective position while(num > 0){ rem = num%10; sum = sum + (int)pow(rem,len); num = num/10; len; } //Checks whether the sum is equal to the number itself if(sum == n) printf("%d is a disarium number", n); else printf("%d is not a disarium number", n); return 0; } Output: 175 is a disarium number JAVApublic class DisariumNumber { //calculateLength() will count the digits present in a number public static int calculateLength(int n){ int length = 0; while(n != 0){ length = length + 1; n = n/10; } return length; } public static void main(String[] args) { int num = 175, sum = 0, rem = 0, n; int len = calculateLength(num); //Makes a copy of the original number num n = num; //Calculates the sum of digits powered with their respective position while(num > 0){ rem = num%10; sum = sum + (int)Math.pow(rem,len); num = num/10; len; } //Checks whether the sum is equal to the number itself if(sum == n) System.out.println(n + " is a disarium number"); else System.out.println(n + " is not a disarium number"); } } Output: 175 is a disarium number C#using System; public class DisariumNumber { //calculateLength() will count the digits present in a number public static int calculateLength(int n){ int length = 0; while(n != 0){ length = length + 1; n = n/10; } return length; } public static void Main() { int num = 175, sum = 0, rem = 0, n; int len = calculateLength(num); //Makes a copy of the original number num n = num; //Calculates the sum of digits powered with their respective position while(num > 0){ rem = num%10; sum = sum + (int)Math.Pow(rem,len); num = num/10; len; } //Checks whether the sum is equal to the number itself if(sum == n) Console.WriteLine(n + " is a disarium number"); else Console.WriteLine(n + " is not a disarium number"); } } Output: 175 is a disarium number PHP<!DOCTYPE html> <html> <body> <?php //calculateLength() will count the digits present in a number function calculateLength($n){ $length = 0; while($n != 0){ $length = $length + 1; $n = intval($n/10); } return $length; } $num = 175; $rem = $sum = 0; $len = calculateLength($num); //Makes a copy of the original number num $n = $num; //Calculates the sum of digits powered with their respective position while($num > 0){ $rem = $num%10; $sum = $sum + pow($rem,$len); $num = intval($num/10); $len; } //Checks whether sum is equal to the number itself if($sum == $n) print($n . " is a disarium number"); else print($n . " is not a disarium number"); ?> </body> </html> Output: 175 is a disarium number
Next Topic#
