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Program To Create A Singly Linked List Of N Nodes And Count The Number Of Nodes

Program To Create A Singly Linked List Of N Nodes And Count The Number Of Nodes on fibonacci, factorial, prime, armstrong, swap, reverse, search, sort, stack, queue, array, linkedlist, tree, graph etc.

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Program to create a singly linked list of n nodes and count the number of nodes

Explanation

In this program, we need to create a singly linked list and count the nodes present in the list.

Program to create a singly linked list of n nodes and count the number of nodes

To accomplish this task, traverse through the list using node current which initially points to head. Increment current in such a way that current will point to its next node in each iteration and increment variable count by 1. In the end, the count will hold the value which denotes the number of nodes present in the list.

Algorithm

  1. Create a class Node which has two attributes: data and next. Next is a pointer to the next node in the list.
  2. Create another class which has two attributes: head and tail.
  3. addNode() will add a new node to the list:
    1. Create a new node.
    2. It first checks, whether the head is equal to null which means the list is empty.
    3. If the list is empty, both head and tail will point to the newly added node.
    4. If the list is not empty, the new node will be added to end of the list such that tail's next will point to a newly added node. This new node will become the new tail of the list.
  4. countNodes() will count the nodes present in the list:
    1. Define a node current which will initially point to the head of the list.
    2. Declare and initialize a variable count to 0.
    3. Traverse through the list till current point to null.
    4. Increment the value of count by 1 for each node encountered in the list.
  5. display() will display the nodes present in the list:
    1. Define a node current which will initially point to the head of the list.
    2. Traverse through the list till current points to null.
    3. Display each node by making current to point to node next to it in each iteration.

Solution

Python

#Represent a node of the singly linked list
class Node:
    def __init__(self,data):
        self.data = data;
        self.next = None;
        
class CountNodes:
    #Represent the head and tail of the singly linked list
    def __init__(self):
        self.head = None;
        self.tail = None;
        
    #addNode() will add a new node to the list
    def addNode(self, data):
        #Create a new node
        newNode = Node(data);
        
        #Checks if the list is empty
        if(self.head == None):
            #If list is empty, both head and tail will point to new node
            self.head = newNode;
            self.tail = newNode;
        else:
            #newNode will be added after tail such that tail's next will point to newNode
            self.tail.next = newNode;
            #newNode will become new tail of the list
            self.tail = newNode;
            
    #countNodes() will count the nodes present in the list
    def countNodes(self):
        count = 0;
        #Node current will point to head
        current = self.head;
        
        while(current != None):
            #Increment the count by 1 for each node
            count = count + 1;
            current = current.next;
        return count;
    
    #display() will display all the nodes present in the list
    def display(self):
        #Node current will point to head
        current = self.head;
        
        if(self.head == None):
            print("List is empty");
            return;
        print("Nodes of singly linked list: ");
        while(current != None):
            #Prints each node by incrementing pointer
            print(current.data),
            current = current.next;
     
 
sList = CountNodes();
        
#Add nodes to the list
sList.addNode(1);
sList.addNode(2);
sList.addNode(3);
sList.addNode(4);
 
#Displays the nodes present in the list
sList.display();
 
#Counts the nodes present in the given list
print("Count of nodes present in the list: " + str(sList.countNodes()));

Output:

 Nodes of singly linked list: 
1 2 3 4 
Count of nodes present in the list: 4

C

#include <stdio.h>
 
//Represent a node of singly linked list
struct node{
    int data;
    struct node *next;
};    
 
//Represent the head and tail of the singly linked list
struct node *head, *tail = NULL;
 
//addNode() will add a new node to the list
void addNode(int data) {
    //Create a new node
    struct node *newNode = (struct node*)malloc(sizeof(struct node));
    newNode->data = data;
    newNode->next = NULL;
    
    //Checks if the list is empty
    if(head == NULL) {
        //If list is empty, both head and tail will point to new node
        head = newNode;
        tail = newNode;
    }
    else {
        //newNode will be added after tail such that tail's next will point to newNode
        tail->next = newNode;
        //newNode will become new tail of the list
        tail = newNode;
    }
}
 
//countNodes() will count the nodes present in the list
int countNodes() {
    int count = 0;
    //Node current will point to head
    struct node *current = head;
    
    while(current != NULL) {
        //Increment the count by 1 for each node
        count++;
        current = current->next;
    }
    return count;
}
    
//display() will display all the nodes present in the list
void display() {
    //Node current will point to head
    struct node *current = head;
    
    if(head == NULL) {
        printf("List is empty\n");
        return;
    }
    printf("Nodes of singly linked list: \n");
    while(current != NULL) {
        //Prints each node by incrementing pointer
        printf("%d ", current->data);
        current = current->next;
    }
    printf("\n");
}
    
int main()
{
    //Add nodes to the list
    addNode(1);
    addNode(2);
    addNode(3);
    addNode(4);
    
    //Displays the nodes present in the list
    display();
    
    //Counts the nodes present in the given list
    printf("Count of nodes present in the list: %d", countNodes());
 
    return 0;
}

Output:

Nodes of singly linked list: 
1 2 3 4 
Count of nodes present in the list: 4

JAVA

public class CountNodes {
    
    //Represent a node of singly linked list
    class Node{
        int data;
        Node next;
        
        public Node(int data) {
            this.data = data;
            this.next = null;
        }
    }
 
    //Represent the head and tail of the singly linked list
    public Node head = null;
    public Node tail = null;
    
    //addNode() will add a new node to the list
    public void addNode(int data) {
        //Create a new node
        Node newNode = new Node(data);
        
        //Checks if the list is empty
        if(head == null) {
            //If list is empty, both head and tail will point to new node
            head = newNode;
            tail = newNode;
        }
        else {
            //newNode will be added after tail such that tail's next will point to newNode
            tail.next = newNode;
            //newNode will become new tail of the list
            tail = newNode;
        }
    }
    
    //countNodes() will count the nodes present in the list
    public int countNodes() {
        int count = 0;
        //Node current will point to head
        Node current = head;
        
        while(current != null) {
            //Increment the count by 1 for each node
            count++;
            current = current.next;
        }
        return count;
    }
        
    //display() will display all the nodes present in the list
    public void display() {
        //Node current will point to head
        Node current = head;
        if(head == null) {
            System.out.println("List is empty");
            return;
        }
        System.out.println("Nodes of singly linked list: ");
        while(current != null) {
            //Prints each node by incrementing pointer
            System.out.print(current.data + " ");
            current = current.next;
        }
        System.out.println();
    }
    
    public static void main(String[] args) {
        
        CountNodes sList = new CountNodes();
        
        //Add nodes to the list
        sList.addNode(1);
        sList.addNode(2);
        sList.addNode(3);
        sList.addNode(4);
        
        //Displays the nodes present in the list
        sList.display();
        
        //Counts the nodes present in the given list
        System.out.println("Count of nodes present in the list: " + sList.countNodes());
    }
}

Output:

Nodes of the singly linked list:
1 2 3 4 
Count of nodes present in the list: 4

C#

using System;
                    
public class CountNodes
{
    //Represent a node of singly linked list
    public class Node<T>{
        public T data;
        public Node<T> next;
        
        public Node(T value) {
            data = value;
            next = null;
        }
    }
        
    public class SinglyLinkedList<T>{
        //Represent the head and tail of the singly linked list
        public Node<T> head = null;             
         public Node<T> tail = null;
    
        //addNode() will add a new node to the list
        public void addNode(T data) {
            //Create a new node
            Node<T> newNode = new Node<T>(data);
 
            //Checks if the list is empty
            if(head == null) {
                //If list is empty, both head and tail will point to new node
                head = newNode;
                tail = newNode;
            }
            else {
                //newNode will be added after tail such that tail's next will point to newNode
                tail.next = newNode;
                //newNode will become new tail of the list
                tail = newNode;
            }
        }
        
        //countNodes() will count the nodes present in the list
        public int countNodes() {
            int count = 0;
            //Node current will point to head
            Node<T> current = head;
 
            while(current != null) {
                //Increment the count by 1 for each node
                count++;
                current = current.next;
            }
            return count;
        }
        
        //display() will display all the nodes present in the list
        public void display() {
            //Node current will point to head
            Node<T> current = head;
            
            if(head == null) {
                Console.WriteLine("List is empty");
                return;
            }
            Console.WriteLine("Nodes of singly linked list: ");
            while(current != null) {
                //Prints each node by incrementing pointer
                Console.Write(current.data + " ");
                current = current.next;
            }
            Console.WriteLine();
        }
    }
    
    public static void Main()
    {
        SinglyLinkedList<int> sList = new SinglyLinkedList<int>();
        
        //Add nodes to the list
        sList.addNode(1);
        sList.addNode(2);
        sList.addNode(3);
        sList.addNode(4);
        
        //Displays the nodes present in the list
        sList.display();    
        
        //Counts the nodes present in the given list
        Console.WriteLine("Count of nodes present in the list: " + sList.countNodes());
    }
}

Output:

Nodes of singly linked list: 
1 2 3 4 
Count of nodes present in the list: 4

PHP

<!DOCTYPE html>
<html>
<body>
<?php
//Represent a node of singly linked list
class Node{
    public $data;
    public $next;
    
    function __construct($data){
        $this->data = $data;
        $this->next = NULL;
    }
}
class CountNodes{
    //Represent the head and tail of the singly linked list
    public $head;
    public $tail;
    function __construct(){
        $this->head = NULL;
        $this->tail = NULL;
    }
    
    //addNode() will add a new node to the list
    function addNode($data) {
        //Create a new node
        $newNode = new Node($data);
        
        //Checks if the list is empty
        if($this->head == NULL) {
            //If list is empty, both head and tail will point to new node
            $this->head = $newNode;
            $this->tail = $newNode;
        }
        else {
            //newNode will be added after tail such that tail's next will point to newNode
            $this->tail->next = $newNode;
            //newNode will become new tail of the list
            $this->tail = $newNode;
        }
    }
    
    //countNodes() will count the nodes present in the list
    function countNodes() {
        $count = 0;
        //Node current will point to head
        $current = $this->head;
        
        while($current != NULL) {
            //Increment the count by 1 for each node
            $count++;
            $current = $current->next;
        }
        return $count;
    }    
    
    //display() will display all the nodes present in the list
    function display() {
        //Node current will point to head
        $current = $this->head;
        
        if($this->head == NULL) {
            print("List is empty <br>");
            return;
        }
        print("Nodes of singly linked list: <br>");
        while($current != NULL) {
            //Prints each node by incrementing pointer
            print($current->data . " ");
            $current = $current->next;
        }
        print("<br>");
    }
}
    
$sList = new CountNodes();
        
//Add nodes to the list
$sList->addNode(1);
$sList->addNode(2);
$sList->addNode(3);
$sList->addNode(4);
 
//Displays the nodes present in the list
$sList->display();
    
//Counts the nodes present in the given list
print("Count of nodes present in the list: " . $sList->countNodes());
?>
</body>
</html>

Output:

Nodes of singly linked list: 
1 2 3 4 
Count of nodes present in the list: 4

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