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Q. Program to find the maximum and minimum value node from a doubly linked list.
ExplanationIn this program, we will create a doubly linked list then, iterate through the list to find out the minimum and maximum node.
We will maintain two variables min and max. Min will hold the minimum value node, and max will hold the maximum value node. In above example, 1 will be the minimum value node and 9 will be the maximum value node. Algorithm
Solution
Python
#Represent a node of doubly linked list
class Node:
def __init__(self,data):
self.data = data;
self.previous = None;
self.next = None;
class MinMax:
#Represent the head and tail of the doubly linked list
def __init__(self):
self.head = None;
self.tail = None;
#addNode() will add a node to the list
def addNode(self, data):
#Create a new node
newNode = Node(data);
#If list is empty
if(self.head == None):
#Both head and tail will point to newNode
self.head = self.tail = newNode;
#head's previous will point to None
self.head.previous = None;
#tail's next will point to None, as it is the last node of the list
self.tail.next = None;
else:
#newNode will be added after tail such that tail's next will point to newNode
self.tail.next = newNode;
#newNode's previous will point to tail
newNode.previous = self.tail;
#newNode will become new tail
self.tail = newNode;
#As it is last node, tail's next will point to None
self.tail.next = None;
#MinimumNode() will find out minimum value node in the list
def minimumNode(self):
#Node current will point to head
current = self.head;
#Checks if list is empty
if(self.head == None):
print("List is empty");
return 0;
else:
#Initially, min will store the value of head's data
min = self.head.data;
while(current != None):
#If value of min is greater than current's data
#Then, replace value of min with current node's data
if(min > current.data):
min = current.data;
current = current.next;
return min;
#MaximumNode() will find out maximum value node in the list
def maximumNode(self):
#Node current will point to head
current = self.head;
#Checks if list is empty
if(self.head == None):
print("List is empty");
return 0;
else:
#Initially, max will store the value of head's data
max = self.head.data;
#If value of max is lesser than current's data
#Then, replace value of max with current node's data
while(current != None):
if(current.data > max):
max = current.data;
current = current.next;
return max;
dList = MinMax();
#Add nodes to the list
dList.addNode(5);
dList.addNode(7);
dList.addNode(9);
dList.addNode(1);
dList.addNode(2);
#Prints the minimum value node in the list
print("Minimum value node in the list: "+ str(dList.minimumNode()));
#Prints the maximum value node in the list
print("Maximum value node in the list: "+ str(dList.maximumNode()));
Output: Minimum value node in the list: 1 Maximum value node in the list: 9 C
#include <stdio.h>
//Represent a node of the doubly linked list
struct node{
int data;
struct node *previous;
struct node *next;
};
//Represent the head and tail of the doubly linked list
struct node *head, *tail = NULL;
//addNode() will add a node to the list
void addNode(int data) {
//Create a new node
struct node *newNode = (struct node*)malloc(sizeof(struct node));
newNode->data = data;
//If list is empty
if(head == NULL) {
//Both head and tail will point to newNode
head = tail = newNode;
//head's previous will point to NULL
head->previous = NULL;
//tail's next will point to NULL, as it is the last node of the list
tail->next = NULL;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
tail->next = newNode;
//newNode's previous will point to tail
newNode->previous = tail;
//newNode will become new tail
tail = newNode;
//As it is last node, tail's next will point to NULL
tail->next = NULL;
}
}
//MinimumNode() will find out minimum value node in the list
int minimumNode() {
//Node current will point to head
struct node *current = head;
int min;
//Checks if list is empty
if(head == NULL) {
printf("List is empty\n");
return 0;
}
else {
//Initially, min will store the value of head's data
min = head->data;
while(current != NULL) {
//If value of min is greater than current's data
//Then, replace value of min with current node's data
if(min > current->data)
min = current->data;
current = current->next;
}
}
return min;
}
//MaximumNode() will find out maximum value node in the list
int maximumNode() {
//Node current will point to head
struct node *current = head;
int max;
//Checks if list is empty
if(head == NULL) {
printf("List is empty\n");
return 0;
}
else {
//Initially, max will store the value of head's data
max = head->data;
//If value of max is lesser than current's data
//Then, replace value of max with current node's data
while(current != NULL) {
if(current->data > max)
max = current->data;
current = current->next;
}
}
return max;
}
int main()
{
//Add nodes to the list
addNode(5);
addNode(7);
addNode(9);
addNode(1);
addNode(2);
//Prints the minimum value node in the list
printf("Minimum value node in the list: %d\n", minimumNode());
//Prints the maximum value node in the list
printf("Maximum value node in the list: %d", maximumNode());
return 0;
}
Output: Minimum value node in the list: 1 Maximum value node in the list: 9 JAVA
public class MinMax {
//Represent a node of the doubly linked list
class Node{
int data;
Node previous;
Node next;
public Node(int data) {
this.data = data;
}
}
//Represent the head and tail of the doubly linked list
Node head, tail = null;
//addNode() will add a node to the list
public void addNode(int data) {
//Create a new node
Node newNode = new Node(data);
//If list is empty
if(head == null) {
//Both head and tail will point to newNode
head = tail = newNode;
//head's previous will point to null
head.previous = null;
//tail's next will point to null, as it is the last node of the list
tail.next = null;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
tail.next = newNode;
//newNode's previous will point to tail
newNode.previous = tail;
//newNode will become new tail
tail = newNode;
//As it is last node, tail's next will point to null
tail.next = null;
}
}
//MinimumNode() will find out minimum value node in the list
public int minimumNode() {
//Node current will point to head
Node current = head;
int min;
//Checks if list is empty
if(head == null) {
System.out.println("List is empty");
return 0;
}
else {
//Initially, min will store the value of head's data
min = head.data;
while(current != null) {
//If the value of min is greater than the current's data
//Then, replace the value of min with current node's data
if(min > current.data)
min = current.data;
current = current.next;
}
}
return min;
}
//MaximumNode() will find out maximum value node in the list
public int maximumNode() {
//Node current will point to head
Node current = head;
int max;
//Checks if list is empty
if(head == null) {
System.out.println("List is empty");
return 0;
}
else {
//Initially, max will store the value of head's data
max = head.data;
//If value of max is lesser than current's data
//Then, replace value of max with current node's data
while(current != null) {
if(current.data > max)
max = current.data;
current = current.next;
}
}
return max;
}
public static void main(String[] args) {
MinMax dList = new MinMax();
//Add nodes to the list
dList.addNode(5);
dList.addNode(7);
dList.addNode(9);
dList.addNode(1);
dList.addNode(2);
//Prints the minimum value node in the list
System.out.println("Minimum value node in the list: "+ dList.minimumNode());
//Prints the maximum value node in the list
System.out.println("Maximum value node in the list: "+ dList.maximumNode());
}
}
Output: Minimum value node in the list: 1 Maximum value node in the list: 9 C#
using System;
namespace DoublyLinkedList
{
public class Program
{
//Represent a node of the doubly linked list
public class Node<T>{
public T data;
public Node<T> previous;
public Node<T> next;
public Node(T value) {
data = value;
}
}
public class MinMax<T> where T : IComparable<T>{
//Represent the head and tail of the doubly linked list
protected Node<T> head = null;
protected Node<T> tail = null;
//addNode() will add a node to the list
public void addNode(T data) {
//Create a new node
Node<T> newNode = new Node<T>(data);
//If list is empty
if(head == null) {
//Both head and tail will point to newNode
head = tail = newNode;
//head's previous will point to null
head.previous = null;
//tail's next will point to null, as it is the last node of the list
tail.next = null;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
tail.next = newNode;
//newNode's previous will point to tail
newNode.previous = tail;
//newNode will become new tail
tail = newNode;
//As it is last node, tail's next will point to null
tail.next = null;
}
}
//MinimumNode() will find out minimum value node in the list
public T minimumNode() {
//Node current will point to head
Node<T> current = head;
T min;
//Checks if list is empty
if(head == null) {
Console.WriteLine("List is empty");
return default(T);
}
else {
//Initially, min will store the value of head's data
min = head.data;
while(current != null) {
//If value of min is greater than current's data
//Then, replace value of min with current node's data
if(min.CompareTo(current.data) > 0)
min = current.data;
current = current.next;
}
}
return min;
}
//MaximumNode() will find out maximum value node in the list
public T maximumNode() {
//Node current will point to head
Node<T> current = head;
T max;
//Checks if list is empty
if(head == null) {
Console.WriteLine("List is empty");
return default(T);
}
else {
//Initially, max will store the value of head's data
max = head.data;
//If value of max is lesser than current's data
//Then, replace value of max with current node's data
while(current != null) {
if(current.data.CompareTo(max) > 0)
max = current.data;
current = current.next;
}
}
return max;
}
}
public static void Main()
{
MinMax<int> dList = new MinMax<int>();
//Add nodes to the list
dList.addNode(5);
dList.addNode(7);
dList.addNode(9);
dList.addNode(1);
dList.addNode(2);
//Prints the minimum value node in the list
Console.WriteLine("Minimum value node in the list: "+ dList.minimumNode());
//Prints the maximum value node in the list
Console.WriteLine("Maximum value node in the list: "+ dList.maximumNode());
}
}
}
Output: Minimum value node in the list: 1 Maximum value node in the list: 9 PHP
<!DOCTYPE html>
<html>
<body>
<?php
//Represent a node of doubly linked list
class Node{
public $data;
public $previous;
public $next;
function __construct($data){
$this->data = $data;
}
}
class MinMax{
//Represent the head and tail of the doubly linked list
public $head;
public $tail;
function __construct(){
$this->head = NULL;
$this->tail = NULL;
}
//addNode() will add a node to the list
function addNode($data){
//Create a new node
$newNode = new Node($data);
//If list is empty
if($this->head == NULL) {
//Both head and tail will point to newNode
$this->head = $this->tail = $newNode;
//head's previous will point to NULL
$this->head->previous = NULL;
//tail's next will point to NULL, as it is the last node of the list
$this->tail->next = NULL;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
$this->tail->next = $newNode;
//newNode's previous will point to tail
$newNode->previous = $this->tail;
//newNode will become new tail
$this->tail = $newNode;
//As it is last node, tail's next will point to NULL
$this->tail->next = NULL;
}
}
//MinimumNode() will find out minimum value node in the list
function minimumNode() {
//Node current will point to head
$current = $this->head;
//Checks if list is empty
if($this->head == NULL) {
print("List is empty <br>");
return 0;
}
else {
//Initially, min will store the value of head's data
$min = $this->head->data;
while($current != NULL) {
//If value of min is greater than current's data
//Then, replace value of min with current node's data
if($min > $current->data)
$min = $current->data;
$current = $current->next;
}
}
return $min;
}
//MaximumNode() will find out maximum value node in the list
function maximumNode() {
//Node current will point to head
$current = $this->head;
//Checks if list is empty
if($this->head == NULL) {
print("List is empty <br>");
return 0;
}
else {
//Initially, max will store the value of head's data
$max = $this->head->data;
//If value of max is lesser than current's data
//Then, replace value of max with current node's data
while($current != NULL) {
if($current->data > $max)
$max = $current->data;
$current = $current->next;
}
}
return $max;
}
}
$dList = new MinMax();
//Add nodes to the list
$dList->addNode(5);
$dList->addNode(7);
$dList->addNode(9);
$dList->addNode(1);
$dList->addNode(2);
//Prints the minimum value node in the list
print("Minimum value node in the list: " . $dList->minimumNode());
print("<br>");
//Prints the maximum value node in the list
print("Maximum value node in the list: " . $dList->maximumNode());
?>
</body>
</html>
Output: Minimum value node in the list: 1 Maximum value node in the list: 9
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