Program to print the sum of digits without using modulus

Program to print the sum of digits without using modulus on fibonacci, factorial, prime, armstrong, swap, reverse, search, sort, stack, queue, array, linkedlist, tree, graph, pattern, string etc.

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Program to print the sum of digits without using modulus

In this program, we have to add the digits of the entry number without the logic of using modulus(%).

Example:

149: the sum of its digits (1, 4, 9) is 14.

Go through the algorithm to code for this program:

Algorithm

STEP 1: START
STEP 2: ENTER n as a string
STEP 3: SET sum =0
STEP 4: SET i = 0
STEP 4: REPEAT STEP 5 and 6 UNTIL (i<length(n))
STEP 5: sum =sum + n[i]
STEP 6: sum = sum - 48
STEP 7: i = i+1
STEP 7: PRINT sum
STEP 8: END

Java Program

import java.util.*;
class SumOfDigits {
    public static void main(String[] args) {
   Scanner sc = new Scanner(System.in); 
  System.out.println("Enter the number?");
  String str=sc.nextLine();
   char[] n = str.toCharArray();
   int sum=0;
for(int i =0;i<n.length;i++)
{
   sum = sum + ((int)n[i]);
   sum = sum-48;
}
System.out.println("sum of digits: "+sum);
}   
}

Output:

Enter the number?
345
sum of digits: 12

C Program

#include <stdio.h>
int main()
{
   int c, sum, t;
   char n[1000];
   printf("Enter the number?");
   scanf("%s", n);
   sum = c = 0;
   while (n[c] != '\0') {
      t   = n[c] - '0'; 
      sum = sum + t;
      c++;
   }
   printf("sum of digits: %d",sum);
   return 0;
}

Output:

Enter the number? 45
sum of digits: 9

C# Program

using System;
public class Sum_Of_Digits
{
public static void Main()
{
	int sum=0,i;
	Console.WriteLine("Enter the number?");
string str = Console.ReadLine();
char[] c = str.ToCharArray();
for(i =0;i<c.Length;i++)
{
   sum = sum + ((int)c[i]);
   sum = sum-48;
}
Console.WriteLine("sum of digits: "+sum);
}
}

Output:

Enter the number? 75
sum of digits: 12

Python Program

sum=0
Str = input("Enter the number?");
for i in range(len(Str)):
    sum = sum + (int(Str[i]))

print ("sum of digits: %d"%(sum) )

Output:

	Enter the number? 175
	sum of digits: 13

PHP Program

<?php
	echo("Enter the number?");
	$n=readline();
	$sum = 0;
	$c = 0;
	for($c = 0;$c<strlen($n);$c++){
   	   $t   = $n[$c] - '0'; 
      	   $sum = $sum + $t;
 	  }
   echo("sum of digits:");
   echo($sum);
?>

Output:

Enter the number? 175
sum of digits: 13

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Program to print the sum of digits without using modulus