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Program to delete a node from the end of the singly linked list
ExplanationIn this program, we will create a singly linked list and delete a node from the end of the list. To accomplish this task, we first find out the second last node of the list. Then, make second last node as the new tail of the list. Then, delete the last node of the list.
In the above example, Node was the tail of the list. Traverse through the list to find out the second last node which in this case is node 4. Make node 4 as the tail of the list. Node 4's next will point to null. Algorithm
SolutionPython
#Represent a node of the singly linked list
class Node:
def __init__(self,data):
self.data = data;
self.next = None;
class DeleteEnd:
#Represent the head and tail of the singly linked list
def __init__(self):
self.head = None;
self.tail = None;
#addNode() will add a new node to the list
def addNode(self, data):
#Create a new node
newNode = Node(data);
#Checks if the list is empty
if(self.head == None):
#If list is empty, both head and tail will point to new node
self.head = newNode;
self.tail = newNode;
else:
#newNode will be added after tail such that tail's next will point to newNode
self.tail.next = newNode;
#newNode will become new tail of the list
self.tail = newNode;
#deleteFromEnd() will delete a node from end of the list
def deleteFromEnd(self):
#Checks if the list is empty
if(self.head == None):
print("List is empty");
return;
else:
#Checks whether the list contains only one element
if(self.head != self.tail):
current = self.head;
#Loop through the list till the second last element such that current.next is pointing to tail
while(current.next != self.tail):
current = current.next;
#Second last element will become new tail of the list
self.tail = current;
self.tail.next = None;
#If the list contains only one element
#Then it will remove it, and both head and tail will point to None
else:
self.head = self.tail = None;
#display() will display all the nodes present in the list
def display(self):
#Node current will point to head
current = self.head;
if(self.head == None):
print("List is empty");
return;
while(current != None):
#Prints each node by incrementing pointer
print(current.data),
current = current.next;
sList = DeleteEnd();
#Adds data to the list
sList.addNode(1);
sList.addNode(2);
sList.addNode(3);
sList.addNode(4);
#Printing original list
print("Original List: ");
sList.display();
while(sList.head != None):
sList.deleteFromEnd();
#Printing updated list
print("Updated List: ");
sList.display();
Output: Original List: 1 2 3 4 Updated List: 1 2 3 Updated List: 1 2 Updated List: 1 Updated List: List is empty C
#include <stdio.h>
//Represent a node of the singly linked list
struct node{
int data;
struct node *next;
};
//Represent the head and tail of the singly linked list
struct node *head, *tail = NULL;
//addNode() will add a new node to the list
void addNode(int data) {
//Create a new node
struct node *newNode = (struct node*)malloc(sizeof(struct node));
newNode->data = data;
newNode->next = NULL;
//Checks if the list is empty
if(head == NULL) {
//If list is empty, both head and tail will point to new node
head = newNode;
tail = newNode;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
tail->next = newNode;
//newNode will become new tail of the list
tail = newNode;
}
}
//deleteFromEnd() will delete a node from end of the list
void deleteFromEnd() {
//Checks if the list is empty
if(head == NULL) {
printf("List is empty \n");
return;
}
else {
//Checks whether the list contains only one element
if(head != tail ) {
struct node *current = head;
//Loop through the list till the second last element such that current.next is pointing to tail
while(current->next != tail) {
current = current->next;
}
//Second last element will become new tail of the list
tail = current;
tail->next = NULL;
}
//If the list contains only one element
//Then it will remove it and both head and tail will point to NULL
else {
head = tail = NULL;
}
}
}
//display() will display all the nodes present in the list
void display() {
//Node current will point to head
struct node *current = head;
if(head == NULL) {
printf("List is empty\n");
return;
}
while(current != NULL) {
//Prints each node by incrementing pointer
printf("%d ", current->data);
current = current->next;
}
printf("\n");
}
int main()
{
//Adds data to the list
addNode(1);
addNode(2);
addNode(3);
addNode(4);
//Printing original list
printf("Original List: \n");
display();
while(head != NULL) {
deleteFromEnd();
//Printing updated list
printf("Updated List: \n");
display();
}
return 0;
}
Output: Original List: 1 2 3 4 Updated List: 1 2 3 Updated List: 1 2 Updated List: 1 Updated List: List is empty JAVA
public class DeleteEnd {
//Represent a node of the singly linked list
class Node{
int data;
Node next;
public Node(int data) {
this.data = data;
this.next = null;
}
}
//Represent the head and tail of the singly linked list
public Node head = null;
public Node tail = null;
//addNode() will add a new node to the list
public void addNode(int data) {
//Create a new node
Node newNode = new Node(data);
//Checks if the list is empty
if(head == null) {
//If list is empty, both head and tail will point to new node
head = newNode;
tail = newNode;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
tail.next = newNode;
//newNode will become new tail of the list
tail = newNode;
}
}
//deleteFromEnd() will delete a node from end of the list
public void deleteFromEnd() {
//Checks if the list is empty
if(head == null) {
System.out.println("List is empty");
return;
}
else {
//Checks whether the list contains only one element
if(head != tail ) {
Node current = head;
//Loop through the list till the second last element such that current.next is pointing to tail
while(current.next != tail) {
current = current.next;
}
//Second last element will become new tail of the list
tail = current;
tail.next = null;
}
//If the list contains only one element
//Then it will remove it and both head and tail will point to null
else {
head = tail = null;
}
}
}
//display() will display all the nodes present in the list
public void display() {
//Node current will point to head
Node current = head;
if(head == null) {
System.out.println("List is empty");
return;
}
while(current != null) {
//Prints each node by incrementing pointer
System.out.print(current.data + " ");
current = current.next;
}
System.out.println();
}
public static void main(String[] args) {
DeleteEnd sList = new DeleteEnd();
//Adds data to the list
sList.addNode(1);
sList.addNode(2);
sList.addNode(3);
sList.addNode(4);
//Printing original list
System.out.println("Original List: ");
sList.display();
while(sList.head != null) {
sList.deleteFromEnd();
//Printing updated list
System.out.println("Updated List: ");
sList.display();
}
}
}
Output: Original List: 1 2 3 4 Updated List: 1 2 3 Updated List: 1 2 Updated List: 1 Updated List: List is empty C#
using System;
public class CreateList
{
//Represent a node of the singly linked list
public class Node<T>{
public T data;
public Node<T> next;
public Node(T value) {
data = value;
next = null;
}
}
public class DeleteEnd<T>{
//Represent the head and tail of the singly linked list
public Node<T> head = null;
public Node<T> tail = null;
//addNode() will add a new node to the list
public void addNode(T data) {
//Create a new node
Node<T> newNode = new Node<T>(data);
//Checks if the list is empty
if(head == null) {
//If list is empty, both head and tail will point to new node
head = newNode;
tail = newNode;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
tail.next = newNode;
//newNode will become new tail of the list
tail = newNode;
}
}
//deleteFromEnd() will delete a node from end of the list
public void deleteFromEnd() {
//Checks if the list is empty
if(head == null) {
Console.WriteLine("List is empty");
return;
}
else {
//Checks whether the list contains only one element
if(head != tail ) {
Node<T> current = head;
//Loop through the list till the second last element such that current.next is pointing to tail
while(current.next != tail) {
current = current.next;
}
//Second last element will become new tail of the list
tail = current;
tail.next = null;
}
//If the list contains only one element
//Then it will remove it and both head and tail will point to null
else {
head = tail = null;
}
}
}
//display() will display all the nodes present in the list
public void display() {
//Node current will point to head
Node<T> current = head;
if(head == null) {
Console.WriteLine("List is empty");
return;
}
while(current != null) {
//Prints each node by incrementing pointer
Console.Write(current.data + " ");
current = current.next;
}
Console.WriteLine();
}
}
public static void Main()
{
DeleteEnd<int> sList = new DeleteEnd<int>();
//Adds data to the list
sList.addNode(1);
sList.addNode(2);
sList.addNode(3);
sList.addNode(4);
//Printing original list
Console.WriteLine("Original List: ");
sList.display();
while(sList.head != null) {
sList.deleteFromEnd();
//Printing updated list
Console.WriteLine("Updated List: ");
sList.display();
}
}
}
Output: Original List: 1 2 3 4 Updated List: 1 2 3 Updated List: 1 2 Updated List: 1 Updated List: List is empty PHP
<!DOCTYPE html>
<html>
<body>
<?php
//Represent a node of singly linked list
class Node{
public $data;
public $next;
function __construct($data){
$this->data = $data;
$this->next = NULL;
}
}
class DeleteEnd{
//Represent the head and tail of the singly linked list
public $head;
public $tail;
function __construct(){
$this->head = NULL;
$this->tail = NULL;
}
//addNode() will add a new node to the list
function addNode($data) {
//Create a new node
$newNode = new Node($data);
//Checks if the list is empty
if($this->head == null) {
//If list is empty, both head and tail will point to new node
$this->head = $newNode;
$this->tail = $newNode;
}
else {
//newNode will be added after tail such that tail's next will point to newNode
$this->tail->next = $newNode;
//newNode will become new tail of the list
$this->tail = $newNode;
}
}
//deleteFromEnd() will delete a node from end of the list
function deleteFromEnd() {
//Checks if the list is empty
if($this->head == null) {
print("List is empty");
return;
}
else {
//Checks whether the list contains only one element
if($this->head != $this->tail ) {
$current = $this->head;
//Loop through the list till the second last element such that current.next is pointing to tail
while($current->next != $this->tail) {
$current = $current->next;
}
//Second last element will become new tail of the list
$this->tail = $current;
$this->tail->next = null;
}
//If the list contains only one element
//Then it will remove it and both head and tail will point to null
else {
$this->head = $this->tail = null;
}
}
}
//display() will display all the nodes present in the list
function display() {
//Node current will point to head
$current = $this->head;
if($this->head == NULL) {
print("List is empty <br>");
return;
}
while($current != NULL) {
//Prints each node by incrementing pointer
print($current->data . " ");
$current = $current->next;
}
print("<br>");
}
}
$sList = new DeleteEnd();
//Adds data to the list
$sList->addNode(1);
$sList->addNode(2);
$sList->addNode(3);
$sList->addNode(4);
//Printing original list
print("Original List: <br>");
$sList->display();
while($sList->head != null) {
$sList->deleteFromEnd();
//Printing updated list
print("Updated List: <br>");
$sList->display();
}
?>
</body>
</html>
Output: Original List: 1 2 3 4 Updated List: 1 2 3 Updated List: 1 2 Updated List: 1 Updated List: List is empty
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