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Program to delete a node from the end of the singly linked listExplanationIn this program, we will create a singly linked list and delete a node from the end of the list. To accomplish this task, we first find out the second last node of the list. Then, make second last node as the new tail of the list. Then, delete the last node of the list. In the above example, Node was the tail of the list. Traverse through the list to find out the second last node which in this case is node 4. Make node 4 as the tail of the list. Node 4's next will point to null. Algorithm
SolutionPython#Represent a node of the singly linked list class Node: def __init__(self,data): self.data = data; self.next = None; class DeleteEnd: #Represent the head and tail of the singly linked list def __init__(self): self.head = None; self.tail = None; #addNode() will add a new node to the list def addNode(self, data): #Create a new node newNode = Node(data); #Checks if the list is empty if(self.head == None): #If list is empty, both head and tail will point to new node self.head = newNode; self.tail = newNode; else: #newNode will be added after tail such that tail's next will point to newNode self.tail.next = newNode; #newNode will become new tail of the list self.tail = newNode; #deleteFromEnd() will delete a node from end of the list def deleteFromEnd(self): #Checks if the list is empty if(self.head == None): print("List is empty"); return; else: #Checks whether the list contains only one element if(self.head != self.tail): current = self.head; #Loop through the list till the second last element such that current.next is pointing to tail while(current.next != self.tail): current = current.next; #Second last element will become new tail of the list self.tail = current; self.tail.next = None; #If the list contains only one element #Then it will remove it, and both head and tail will point to None else: self.head = self.tail = None; #display() will display all the nodes present in the list def display(self): #Node current will point to head current = self.head; if(self.head == None): print("List is empty"); return; while(current != None): #Prints each node by incrementing pointer print(current.data), current = current.next; sList = DeleteEnd(); #Adds data to the list sList.addNode(1); sList.addNode(2); sList.addNode(3); sList.addNode(4); #Printing original list print("Original List: "); sList.display(); while(sList.head != None): sList.deleteFromEnd(); #Printing updated list print("Updated List: "); sList.display(); Output: Original List: 1 2 3 4 Updated List: 1 2 3 Updated List: 1 2 Updated List: 1 Updated List: List is empty C#include <stdio.h> //Represent a node of the singly linked list struct node{ int data; struct node *next; }; //Represent the head and tail of the singly linked list struct node *head, *tail = NULL; //addNode() will add a new node to the list void addNode(int data) { //Create a new node struct node *newNode = (struct node*)malloc(sizeof(struct node)); newNode->data = data; newNode->next = NULL; //Checks if the list is empty if(head == NULL) { //If list is empty, both head and tail will point to new node head = newNode; tail = newNode; } else { //newNode will be added after tail such that tail's next will point to newNode tail->next = newNode; //newNode will become new tail of the list tail = newNode; } } //deleteFromEnd() will delete a node from end of the list void deleteFromEnd() { //Checks if the list is empty if(head == NULL) { printf("List is empty \n"); return; } else { //Checks whether the list contains only one element if(head != tail ) { struct node *current = head; //Loop through the list till the second last element such that current.next is pointing to tail while(current->next != tail) { current = current->next; } //Second last element will become new tail of the list tail = current; tail->next = NULL; } //If the list contains only one element //Then it will remove it and both head and tail will point to NULL else { head = tail = NULL; } } } //display() will display all the nodes present in the list void display() { //Node current will point to head struct node *current = head; if(head == NULL) { printf("List is empty\n"); return; } while(current != NULL) { //Prints each node by incrementing pointer printf("%d ", current->data); current = current->next; } printf("\n"); } int main() { //Adds data to the list addNode(1); addNode(2); addNode(3); addNode(4); //Printing original list printf("Original List: \n"); display(); while(head != NULL) { deleteFromEnd(); //Printing updated list printf("Updated List: \n"); display(); } return 0; } Output: Original List: 1 2 3 4 Updated List: 1 2 3 Updated List: 1 2 Updated List: 1 Updated List: List is empty JAVApublic class DeleteEnd { //Represent a node of the singly linked list class Node{ int data; Node next; public Node(int data) { this.data = data; this.next = null; } } //Represent the head and tail of the singly linked list public Node head = null; public Node tail = null; //addNode() will add a new node to the list public void addNode(int data) { //Create a new node Node newNode = new Node(data); //Checks if the list is empty if(head == null) { //If list is empty, both head and tail will point to new node head = newNode; tail = newNode; } else { //newNode will be added after tail such that tail's next will point to newNode tail.next = newNode; //newNode will become new tail of the list tail = newNode; } } //deleteFromEnd() will delete a node from end of the list public void deleteFromEnd() { //Checks if the list is empty if(head == null) { System.out.println("List is empty"); return; } else { //Checks whether the list contains only one element if(head != tail ) { Node current = head; //Loop through the list till the second last element such that current.next is pointing to tail while(current.next != tail) { current = current.next; } //Second last element will become new tail of the list tail = current; tail.next = null; } //If the list contains only one element //Then it will remove it and both head and tail will point to null else { head = tail = null; } } } //display() will display all the nodes present in the list public void display() { //Node current will point to head Node current = head; if(head == null) { System.out.println("List is empty"); return; } while(current != null) { //Prints each node by incrementing pointer System.out.print(current.data + " "); current = current.next; } System.out.println(); } public static void main(String[] args) { DeleteEnd sList = new DeleteEnd(); //Adds data to the list sList.addNode(1); sList.addNode(2); sList.addNode(3); sList.addNode(4); //Printing original list System.out.println("Original List: "); sList.display(); while(sList.head != null) { sList.deleteFromEnd(); //Printing updated list System.out.println("Updated List: "); sList.display(); } } } Output: Original List: 1 2 3 4 Updated List: 1 2 3 Updated List: 1 2 Updated List: 1 Updated List: List is empty C#using System; public class CreateList { //Represent a node of the singly linked list public class Node<T>{ public T data; public Node<T> next; public Node(T value) { data = value; next = null; } } public class DeleteEnd<T>{ //Represent the head and tail of the singly linked list public Node<T> head = null; public Node<T> tail = null; //addNode() will add a new node to the list public void addNode(T data) { //Create a new node Node<T> newNode = new Node<T>(data); //Checks if the list is empty if(head == null) { //If list is empty, both head and tail will point to new node head = newNode; tail = newNode; } else { //newNode will be added after tail such that tail's next will point to newNode tail.next = newNode; //newNode will become new tail of the list tail = newNode; } } //deleteFromEnd() will delete a node from end of the list public void deleteFromEnd() { //Checks if the list is empty if(head == null) { Console.WriteLine("List is empty"); return; } else { //Checks whether the list contains only one element if(head != tail ) { Node<T> current = head; //Loop through the list till the second last element such that current.next is pointing to tail while(current.next != tail) { current = current.next; } //Second last element will become new tail of the list tail = current; tail.next = null; } //If the list contains only one element //Then it will remove it and both head and tail will point to null else { head = tail = null; } } } //display() will display all the nodes present in the list public void display() { //Node current will point to head Node<T> current = head; if(head == null) { Console.WriteLine("List is empty"); return; } while(current != null) { //Prints each node by incrementing pointer Console.Write(current.data + " "); current = current.next; } Console.WriteLine(); } } public static void Main() { DeleteEnd<int> sList = new DeleteEnd<int>(); //Adds data to the list sList.addNode(1); sList.addNode(2); sList.addNode(3); sList.addNode(4); //Printing original list Console.WriteLine("Original List: "); sList.display(); while(sList.head != null) { sList.deleteFromEnd(); //Printing updated list Console.WriteLine("Updated List: "); sList.display(); } } } Output: Original List: 1 2 3 4 Updated List: 1 2 3 Updated List: 1 2 Updated List: 1 Updated List: List is empty PHP<!DOCTYPE html> <html> <body> <?php //Represent a node of singly linked list class Node{ public $data; public $next; function __construct($data){ $this->data = $data; $this->next = NULL; } } class DeleteEnd{ //Represent the head and tail of the singly linked list public $head; public $tail; function __construct(){ $this->head = NULL; $this->tail = NULL; } //addNode() will add a new node to the list function addNode($data) { //Create a new node $newNode = new Node($data); //Checks if the list is empty if($this->head == null) { //If list is empty, both head and tail will point to new node $this->head = $newNode; $this->tail = $newNode; } else { //newNode will be added after tail such that tail's next will point to newNode $this->tail->next = $newNode; //newNode will become new tail of the list $this->tail = $newNode; } } //deleteFromEnd() will delete a node from end of the list function deleteFromEnd() { //Checks if the list is empty if($this->head == null) { print("List is empty"); return; } else { //Checks whether the list contains only one element if($this->head != $this->tail ) { $current = $this->head; //Loop through the list till the second last element such that current.next is pointing to tail while($current->next != $this->tail) { $current = $current->next; } //Second last element will become new tail of the list $this->tail = $current; $this->tail->next = null; } //If the list contains only one element //Then it will remove it and both head and tail will point to null else { $this->head = $this->tail = null; } } } //display() will display all the nodes present in the list function display() { //Node current will point to head $current = $this->head; if($this->head == NULL) { print("List is empty <br>"); return; } while($current != NULL) { //Prints each node by incrementing pointer print($current->data . " "); $current = $current->next; } print("<br>"); } } $sList = new DeleteEnd(); //Adds data to the list $sList->addNode(1); $sList->addNode(2); $sList->addNode(3); $sList->addNode(4); //Printing original list print("Original List: <br>"); $sList->display(); while($sList->head != null) { $sList->deleteFromEnd(); //Printing updated list print("Updated List: <br>"); $sList->display(); } ?> </body> </html> Output: Original List: 1 2 3 4 Updated List: 1 2 3 Updated List: 1 2 Updated List: 1 Updated List: List is empty
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