Program to print all abundant numbers between 1 to 100

Program to print all abundant numbers between 1 to 100 on fibonacci, factorial, prime, armstrong, swap, reverse, search, sort, stack, queue, array, linkedlist, tree, graph, pattern, string etc.

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Program to print all abundant numbers between 1 and 100

The abundant number can be called an excessive number and defined as the number for which the sum of its proper divisors is greater than the number itself.

A first abundant number is the integer 12 having the sum (16) of its proper divisors (1,2,3,4,6) which is greater than itself(12).

Examples: 12, 18, 20, 24, 30, 36

In this program, we have to find all abundant numbers between 1 and 100.

Algorithm

STEP 1: START
STEP 2: DEFINE n, i, j
STEP 3: SET sum =0
STEP 4: SET n =100
STEP 5: REPEAT STEP 6 to STEP 10 UNTIL i<=n
STEP 6: REPEAT STEP 7 and STEP 8 UNTIL j<=i/2
STEP 7: if i%j ==0
STEP 8: sum =sum + j
STEP 9: if sum>i then PRINT i+
STEP 10: SET sum=0
STEP 11: END

Java Program

public class Abundant_number_1to100 {
    public static void main(String[] args) {
         int n, i, j, sum = 0;
n =100;
for (i = 1; i <= n; i++)
{
           for (j = 1; j <= i/2; j++) 
           {
                     if (i % j == 0)
                     {
                                sum = sum + j;
                     }
           }
                if (sum > i)
                        System.out.print( i+" ");
                sum = 0;
}
}   
}

Output:

12 18 20 24 30 36 40 42 48 54 56 60 66 70 72 78 80 84 88 90 96 100

C Program

#include <stdio.h>
  int main () {
        int n, i, j, sum = 0;
        n=100;
        for (i = 1; i <= n; i++) {
                for (j = 1; j <= i/2; j++) {
                        if (i % j == 0) {
                                sum = sum + j;
                        }
                }

                if (sum > i)
                        printf("%d ", i);
                sum = 0;
        }
        printf("\n");
        return 0;
  }

Output:

12 18 20 24 30 36 40 42 48 54 56 60 66 70 72 78 80 84 88 90 96 100

Python Program

n = 101
su = 0
for i in range(1, n):
    for j in range(1, int(i)):
        if (i % j == 0):
            su = su + j
    if (su > i):
        print( i)
    su = 0

Output:

12 18 20 24 30 36 40 42 48 54 56 60 66 70 72 78 80 84 88 90 96 100

PHP Program

<?php 
$n = 100;
$su = 0;
for($i = 1;$i<=$n;$i++)
{
  for($j=1; $j<=$i/2;$j++)
    {
      if ($i % $j == 0){
            $su = $su + $j;
            }
    }
  if ($su > $i)
    {
        echo $i,"��";
    }
    $su = 0;
}
?>

Output:

12 18 20 24 30 36 40 42 48 54 56 60 66 70 72 78 80 84 88 90 96 100

C# program

using System; 
public class Abundant { 
    public static void Main() 
    { 
int n = 100, i ,j;
int su = 0;
for(i = 1;i<=n;i++)
{
  for(j=1; j<=i/2;j++)
    {
      if (i % j == 0){
            su = su + j;
            }
    }
  if (su > i)
    {
        Console.Write(i+" ");
    }
    su = 0;
    }
}
}

Output:

12 18 20 24 30 36 40 42 48 54 56 60 66 70 72 78 80 84 88 90 96 100

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Program to print all abundant numbers between 1 to 100

Program to print all abundant numbers between 1 and 100

Algorithm

Java Program

C Program

Python Program

PHP Program

C# program

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