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Q) Write a program to print the following pattern.
5432* 543*1 54*21 5*321 *4321 Algorithm
Solution:C Program:
#include <stdio.h>
int main()
{
int i,j,lines=5;
for(i=1;i<=lines;i++){// this loop is used to print lines
for(j=lines;j>=1;j--){// this loop is used to print numbers in a line
if(j!=i)
printf("%d",j);
else
printf("*");
}
printf("\n");
}
return 0;
}
Output: 5432* 543*1 54*21 5*321 *4321 Java Program:
public class Main{
public static void main(String []args){
int i,j,lines=5;
for(i=1;i<=lines;i++){// this loop is used to print the lines
for(j=lines;j>=1;j--){// this loop is used to print numbers in a line
if(j!=i)
System.out.print(j);
else
System.out.print("*");
}
System.out.println("");
}
}
}
Output: 5432* 543*1 54*21 5*321 *4321 C# Program:
using System;
public class Program
{
public static void Main()
{
int i,j,lines=5;
for(i=1;i<=lines;i++){// this loop is used to print the lines
for(j=lines;j>=1;j--){// this loop is used to print numbers in a line
if(j!=i)
Console.Write(j);
else
Console.Write("*");
}
Console.WriteLine("\n");
}
}
}
Output: 5432* 543*1 54*21 5*321 *4321 PHP Program:
<?php
$i;
$j;
$lines=5;
for($i=1;$i<=$lines;$i++){// this loop is used to print lines
for($j=$lines;$j>=1;$j--){// this loop used print numbers in a line
if($j!=$i)
echo $j;
else
echo '*';
}
echo "<br>" ;
}
?>
Output: 5432* 543*1 54*21 5*321 *4321 Python Program:
lines=5
i=1
while(i<=lines):# this loop is used to print lines
j=lines
while (j>=1):# this loop is used to print numbers in a line
if j!=i:
print(j, end='', flush=True)
else:
print('*', end='', flush=True)
j=j-1
print("")
i=i+1;
Output: 5432* 543*1 54*21 5*321 *4321
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